
迴圈、條件判斷
//C++ language
#include<bits/stdc++.h>
#define int long long
#define fastio ios_base::sync_with_stdio(0);cin.tie(0)
using namespace std;
signed main(){
fastio;
int n; cin>>n;
cout<<n<<" ";
while(n > 1){
if(n%2) n = n*3 + 1;
else n /= 2;
cout<<n<<" ";
}
cout<<"\n";
return 0;
}

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